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6(x+1)=5(1-x)
We move all terms to the left:
6(x+1)-(5(1-x))=0
We add all the numbers together, and all the variables
6(x+1)-(5(-1x+1))=0
We multiply parentheses
6x-(5(-1x+1))+6=0
We calculate terms in parentheses: -(5(-1x+1)), so:We get rid of parentheses
5(-1x+1)
We multiply parentheses
-5x+5
Back to the equation:
-(-5x+5)
6x+5x-5+6=0
We add all the numbers together, and all the variables
11x+1=0
We move all terms containing x to the left, all other terms to the right
11x=-1
x=-1/11
x=-1/11
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