1/3(6x+24)-20=-1/4(12x+72

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Solution for 1/3(6x+24)-20=-1/4(12x+72 equation: 



1/3(6x+24)-20=-1/4(12x+72

We move all terms to the left:

1/3(6x+24)-20-(-1/4(12x+72)=0



Domain of the equation: 3(6x+24)!=0

x∈R





Domain of the equation: 4(12x+72)-20!=0

We move all terms containing x to the left, all other terms to the right

4(12x+72)!=20

x∈R



We calculate fractions


(4x(1-20)/(3(6x+24)*4(12x+72)-20)+(-(-3x6)/(3(6x+24)*4(12x+72)-20)=0



We calculate terms in parentheses: +(4x(1-20)/(3(6x+24)*4(12x+72)-20)+(-(-3x6)/(3(6x+24)*4(12x+72)-20), so:

4x(1-20)/(3(6x+24)*4(12x+72)-20)+(-(-3x6)/(3(6x+24)*4(12x+72)-20

We add all the numbers together, and all the variables

(-(-3x^6)/(3(6x+24)*4(12x+72)-20+4x(-19)/(3(6x+24)*4(12x+72)-20)

We can not solve this equation

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