6(x+1)=4(1+14x)+6+3x

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Solution for 6(x+1)=4(1+14x)+6+3x equation: 



6(x+1)=4(1+14x)+6+3x

We move all terms to the left:

6(x+1)-(4(1+14x)+6+3x)=0

We add all the numbers together, and all the variables

6(x+1)-(4(14x+1)+6+3x)=0

We multiply parentheses

6x-(4(14x+1)+6+3x)+6=0



We calculate terms in parentheses: -(4(14x+1)+6+3x), so:

4(14x+1)+6+3x

determiningTheFunctionDomain
4(14x+1)+3x+6

We add all the numbers together, and all the variables

3x+4(14x+1)+6

We multiply parentheses

3x+56x+4+6

We add all the numbers together, and all the variables

59x+10

Back to the equation:

-(59x+10)



We get rid of parentheses

6x-59x-10+6=0

We add all the numbers together, and all the variables

-53x-4=0

We move all terms containing x to the left, all other terms to the right

-53x=4

x=4/-53

x=-4/53

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