-6=(k/2)-10

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Solution for -6=(k/2)-10 equation: 



-6=(k/2)-10

We move all terms to the left:

-6-((k/2)-10)=0

We add all the numbers together, and all the variables

-((+k/2)-10)-6=0

We multiply all the terms by the denominator


-((+k-6*2)-10)=0



We calculate terms in parentheses: -((+k-6*2)-10), so:

(+k-6*2)-10

We add all the numbers together, and all the variables

(k-12)-10

We get rid of parentheses

k-12-10

We add all the numbers together, and all the variables

k-22

Back to the equation:

-(k-22)



We get rid of parentheses

-k+22=0

We add all the numbers together, and all the variables

-1k+22=0

We move all terms containing k to the left, all other terms to the right

-k=-22

k=-22/-1

k=+22

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