6(x+1)=132

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Solution for 6(x+1)=132 equation: 



6(x+1)=132

We move all terms to the left:

6(x+1)-(132)=0

We multiply parentheses

6x+6-132=0

We add all the numbers together, and all the variables

6x-126=0

We move all terms containing x to the left, all other terms to the right

6x=126

x=126/6

x=21

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