1/2(z+4)-6=-2z+8

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Solution for 1/2(z+4)-6=-2z+8 equation: 



1/2(z+4)-6=-2z+8

We move all terms to the left:

1/2(z+4)-6-(-2z+8)=0



Domain of the equation: 2(z+4)!=0

z∈R



We get rid of parentheses

1/2(z+4)+2z-8-6=0

We multiply all the terms by the denominator


2z*2(z+4)-8*2(z+4)-6*2(z+4)+1=0

Wy multiply elements

4z^2(z-16z(z-12z(z+1=0

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