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6(x+1)=-2(1-3x)
We move all terms to the left:
6(x+1)-(-2(1-3x))=0
We add all the numbers together, and all the variables
6(x+1)-(-2(-3x+1))=0
We multiply parentheses
6x-(-2(-3x+1))+6=0
We calculate terms in parentheses: -(-2(-3x+1)), so:We get rid of parentheses
-2(-3x+1)
We multiply parentheses
6x-2
Back to the equation:
-(6x-2)
6x-6x+2+6=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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