-3(2v-3)+6v=5+2(7v-1)

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Solution for -3(2v-3)+6v=5+2(7v-1) equation: 



-3(2v-3)+6v=5+2(7v-1)

We move all terms to the left:

-3(2v-3)+6v-(5+2(7v-1))=0

We add all the numbers together, and all the variables

6v-3(2v-3)-(5+2(7v-1))=0

We multiply parentheses

6v-6v-(5+2(7v-1))+9=0



We calculate terms in parentheses: -(5+2(7v-1)), so:

5+2(7v-1)

determiningTheFunctionDomain
2(7v-1)+5

We multiply parentheses

14v-2+5

We add all the numbers together, and all the variables

14v+3

Back to the equation:

-(14v+3)



We add all the numbers together, and all the variables

-(14v+3)+9=0

We get rid of parentheses

-14v-3+9=0

We add all the numbers together, and all the variables

-14v+6=0

We move all terms containing v to the left, all other terms to the right

-14v=-6

v=-6/-14

v=3/7

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