-(6-3x)-3x=3x-5(3x+6)

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Solution for -(6-3x)-3x=3x-5(3x+6) equation: 



-(6-3x)-3x=3x-5(3x+6)

We move all terms to the left:

-(6-3x)-3x-(3x-5(3x+6))=0

We add all the numbers together, and all the variables

-(-3x+6)-3x-(3x-5(3x+6))=0

We add all the numbers together, and all the variables

-3x-(-3x+6)-(3x-5(3x+6))=0

We get rid of parentheses

-3x+3x-(3x-5(3x+6))-6=0



We calculate terms in parentheses: -(3x-5(3x+6)), so:

3x-5(3x+6)

We multiply parentheses

3x-15x-30

We add all the numbers together, and all the variables

-12x-30

Back to the equation:

-(-12x-30)



We add all the numbers together, and all the variables

-(-12x-30)-6=0

We get rid of parentheses

12x+30-6=0

We add all the numbers together, and all the variables

12x+24=0

We move all terms containing x to the left, all other terms to the right

12x=-24

x=-24/12

x=-2

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