6(x+1)/7=1(x+3)/14

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Solution for 6(x+1)/7=1(x+3)/14 equation: 



6(x+1)/7=1(x+3)/14

We move all terms to the left:

6(x+1)/7-(1(x+3)/14)=0

We calculate fractions


6x/()+(-(1(x+3)*7)/()=0



We calculate terms in parentheses: +(-(1(x+3)*7)/(), so:

-(1(x+3)*7)/(

We multiply all the terms by the denominator


-(1(x+3)*7)



We calculate terms in parentheses: -(1(x+3)*7), so:

1(x+3)*7

We multiply parentheses

7x+21

Back to the equation:

-(7x+21)



We get rid of parentheses

-7x-21

Back to the equation:

+(-7x-21)



We get rid of parentheses

6x/()-7x-21=0

We multiply all the terms by the denominator


6x-7x*()-21*()=0

We add all the numbers together, and all the variables

6x-7x*()=0

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