6/7(x+1)=1/14(x+3)

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Solution for 6/7(x+1)=1/14(x+3) equation: 



6/7(x+1)=1/14(x+3)

We move all terms to the left:

6/7(x+1)-(1/14(x+3))=0



Domain of the equation: 7(x+1)!=0

x∈R





Domain of the equation: 14(x+3))!=0

x∈R



We calculate fractions


(84xx/(7(x+1)*14(x+3)))+(-7xx/(7(x+1)*14(x+3)))=0



We calculate terms in parentheses: +(84xx/(7(x+1)*14(x+3))), so:

84xx/(7(x+1)*14(x+3))

We multiply all the terms by the denominator


84xx

Back to the equation:

+(84xx)





We calculate terms in parentheses: +(-7xx/(7(x+1)*14(x+3))), so:

-7xx/(7(x+1)*14(x+3))

We multiply all the terms by the denominator


-7xx

Back to the equation:

+(-7xx)



We get rid of parentheses

84xx-7xx=0

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