6(x+1)-5x=8+2(x-1)*

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Solution for 6(x+1)-5x=8+2(x-1)* equation:



6(x+1)-5x=8+2(x-1)*
We move all terms to the left:
6(x+1)-5x-(8+2(x-1)*)=0
We add all the numbers together, and all the variables
-5x+6(x+1)-(8+2(x-1)*)=0
We multiply parentheses
-5x+6x-(8+2(x-1)*)+6=0
We calculate terms in parentheses: -(8+2(x-1)*), so:
8+2(x-1)*
determiningTheFunctionDomain 2(x-1)*+8
We multiply parentheses
2x-2+8
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
We add all the numbers together, and all the variables
x-(2x+6)+6=0
We get rid of parentheses
x-2x-6+6=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0

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