2x-5(3-2x)=4(x-1)

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Solution for 2x-5(3-2x)=4(x-1) equation: 



2x-5(3-2x)=4(x-1)

We move all terms to the left:

2x-5(3-2x)-(4(x-1))=0

We add all the numbers together, and all the variables

2x-5(-2x+3)-(4(x-1))=0

We multiply parentheses

2x+10x-(4(x-1))-15=0



We calculate terms in parentheses: -(4(x-1)), so:

4(x-1)

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We add all the numbers together, and all the variables

12x-(4x-4)-15=0

We get rid of parentheses

12x-4x+4-15=0

We add all the numbers together, and all the variables

8x-11=0

We move all terms containing x to the left, all other terms to the right

8x=11

x=11/8

x=1+3/8

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