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6(x+1)+2=-6(x-7)-5
We move all terms to the left:
6(x+1)+2-(-6(x-7)-5)=0
We multiply parentheses
6x-(-6(x-7)-5)+6+2=0
We calculate terms in parentheses: -(-6(x-7)-5), so:We add all the numbers together, and all the variables
-6(x-7)-5
We multiply parentheses
-6x+42-5
We add all the numbers together, and all the variables
-6x+37
Back to the equation:
-(-6x+37)
6x-(-6x+37)+8=0
We get rid of parentheses
6x+6x-37+8=0
We add all the numbers together, and all the variables
12x-29=0
We move all terms containing x to the left, all other terms to the right
12x=29
x=29/12
x=2+5/12
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