6(x+1)+1=2x+4(3+x)

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Solution for 6(x+1)+1=2x+4(3+x) equation: 



6(x+1)+1=2x+4(3+x)

We move all terms to the left:

6(x+1)+1-(2x+4(3+x))=0

We add all the numbers together, and all the variables

6(x+1)-(2x+4(x+3))+1=0

We multiply parentheses

6x-(2x+4(x+3))+6+1=0



We calculate terms in parentheses: -(2x+4(x+3)), so:

2x+4(x+3)

We multiply parentheses

2x+4x+12

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

6x-(6x+12)+7=0

We get rid of parentheses

6x-6x-12+7=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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