-2y+2=3(2y+10)

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Solution for -2y+2=3(2y+10) equation: 



-2y+2=3(2y+10)

We move all terms to the left:

-2y+2-(3(2y+10))=0



We calculate terms in parentheses: -(3(2y+10)), so:

3(2y+10)

We multiply parentheses

6y+30

Back to the equation:

-(6y+30)



We get rid of parentheses

-2y-6y-30+2=0

We add all the numbers together, and all the variables

-8y-28=0

We move all terms containing y to the left, all other terms to the right

-8y=28

y=28/-8

y=-3+1/2

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