6(v-1)=8v+2

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Solution for 6(v-1)=8v+2 equation: 



6(v-1)=8v+2

We move all terms to the left:

6(v-1)-(8v+2)=0

We multiply parentheses

6v-(8v+2)-6=0

We get rid of parentheses

6v-8v-2-6=0

We add all the numbers together, and all the variables

-2v-8=0

We move all terms containing v to the left, all other terms to the right

-2v=8

v=8/-2

v=-4

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