20=(1/2)(h-6)h

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Solution for 20=(1/2)(h-6)h equation: 



20=(1/2)(h-6)h

We move all terms to the left:

20-((1/2)(h-6)h)=0



Domain of the equation: 2)(h-6)h)!=0

h∈R



We add all the numbers together, and all the variables

-((+1/2)(h-6)h)+20=0

We multiply parentheses ..

-((+h^2+1/2*-6)h)+20=0

We multiply all the terms by the denominator


-((+h^2+1+20*2*-6)h)=0



We calculate terms in parentheses: -((+h^2+1+20*2*-6)h), so:

(+h^2+1+20*2*-6)h

We multiply parentheses

h^3+40h^2+h-6h

We do not support ehpression: h^3

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