6(v+3)-2v=2(2v+4)-15

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Solution for 6(v+3)-2v=2(2v+4)-15 equation: 



6(v+3)-2v=2(2v+4)-15

We move all terms to the left:

6(v+3)-2v-(2(2v+4)-15)=0

We add all the numbers together, and all the variables

-2v+6(v+3)-(2(2v+4)-15)=0

We multiply parentheses

-2v+6v-(2(2v+4)-15)+18=0



We calculate terms in parentheses: -(2(2v+4)-15), so:

2(2v+4)-15

We multiply parentheses

4v+8-15

We add all the numbers together, and all the variables

4v-7

Back to the equation:

-(4v-7)



We add all the numbers together, and all the variables

4v-(4v-7)+18=0

We get rid of parentheses

4v-4v+7+18=0

We add all the numbers together, and all the variables

25!=0

There is no solution for this equation

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