4x-2(x-3)=-8+5x-4

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Solution for 4x-2(x-3)=-8+5x-4 equation: 



4x-2(x-3)=-8+5x-4

We move all terms to the left:

4x-2(x-3)-(-8+5x-4)=0

We add all the numbers together, and all the variables

4x-2(x-3)-(5x-12)=0

We multiply parentheses

4x-2x-(5x-12)+6=0

We get rid of parentheses

4x-2x-5x+12+6=0

We add all the numbers together, and all the variables

-3x+18=0

We move all terms containing x to the left, all other terms to the right

-3x=-18

x=-18/-3

x=+6

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