28+3y-10=12y-12-4y

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Solution for 28+3y-10=12y-12-4y equation: 



28+3y-10=12y-12-4y

We move all terms to the left:

28+3y-10-(12y-12-4y)=0

We add all the numbers together, and all the variables

3y-(8y-12)+28-10=0

We add all the numbers together, and all the variables

3y-(8y-12)+18=0

We get rid of parentheses

3y-8y+12+18=0

We add all the numbers together, and all the variables

-5y+30=0

We move all terms containing y to the left, all other terms to the right

-5y=-30

y=-30/-5

y=+6

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