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6(u-1)=3u+3-3(-3u-2)
We move all terms to the left:
6(u-1)-(3u+3-3(-3u-2))=0
We multiply parentheses
6u-(3u+3-3(-3u-2))-6=0
We calculate terms in parentheses: -(3u+3-3(-3u-2)), so:We get rid of parentheses
3u+3-3(-3u-2)
determiningTheFunctionDomain 3u-3(-3u-2)+3
We multiply parentheses
3u+9u+6+3
We add all the numbers together, and all the variables
12u+9
Back to the equation:
-(12u+9)
6u-12u-9-6=0
We add all the numbers together, and all the variables
-6u-15=0
We move all terms containing u to the left, all other terms to the right
-6u=15
u=15/-6
u=-2+1/2
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