-6(2x-5)+x=4(x+3)

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Solution for -6(2x-5)+x=4(x+3) equation: 



-6(2x-5)+x=4(x+3)

We move all terms to the left:

-6(2x-5)+x-(4(x+3))=0

We add all the numbers together, and all the variables

x-6(2x-5)-(4(x+3))=0

We multiply parentheses

x-12x-(4(x+3))+30=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

-11x-(4x+12)+30=0

We get rid of parentheses

-11x-4x-12+30=0

We add all the numbers together, and all the variables

-15x+18=0

We move all terms containing x to the left, all other terms to the right

-15x=-18

x=-18/-15

x=1+1/5

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