6(u+3)=-2(2u-4)+6u

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Solution for 6(u+3)=-2(2u-4)+6u equation: 



6(u+3)=-2(2u-4)+6u

We move all terms to the left:

6(u+3)-(-2(2u-4)+6u)=0

We multiply parentheses

6u-(-2(2u-4)+6u)+18=0



We calculate terms in parentheses: -(-2(2u-4)+6u), so:

-2(2u-4)+6u

We add all the numbers together, and all the variables

6u-2(2u-4)

We multiply parentheses

6u-4u+8

We add all the numbers together, and all the variables

2u+8

Back to the equation:

-(2u+8)



We get rid of parentheses

6u-2u-8+18=0

We add all the numbers together, and all the variables

4u+10=0

We move all terms containing u to the left, all other terms to the right

4u=-10

u=-10/4

u=-2+1/2

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