2u-2+2(6u+9)=-2(u+1)

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Solution for 2u-2+2(6u+9)=-2(u+1) equation: 



2u-2+2(6u+9)=-2(u+1)

We move all terms to the left:

2u-2+2(6u+9)-(-2(u+1))=0

We multiply parentheses

2u+12u-(-2(u+1))+18-2=0



We calculate terms in parentheses: -(-2(u+1)), so:

-2(u+1)

We multiply parentheses

-2u-2

Back to the equation:

-(-2u-2)



We add all the numbers together, and all the variables

14u-(-2u-2)+16=0

We get rid of parentheses

14u+2u+2+16=0

We add all the numbers together, and all the variables

16u+18=0

We move all terms containing u to the left, all other terms to the right

16u=-18

u=-18/16

u=-1+1/8

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