3(a+4)+2(-a-4)=72

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Solution for 3(a+4)+2(-a-4)=72 equation: 



3(a+4)+2(-a-4)=72

We move all terms to the left:

3(a+4)+2(-a-4)-(72)=0

We add all the numbers together, and all the variables

3(a+4)+2(-1a-4)-72=0

We multiply parentheses

3a-2a+12-8-72=0

We add all the numbers together, and all the variables

a-68=0

We move all terms containing a to the left, all other terms to the right

a=68

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