y+3/2=(y-4)/3

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Solution for y+3/2=(y-4)/3 equation: 



y+3/2=(y-4)/3

We move all terms to the left:

y+3/2-((y-4)/3)=0

We calculate fractions


y+(-((y-4)*2)/()+()/()=0



We calculate terms in parentheses: +(-((y-4)*2)/()+()/(), so:

-((y-4)*2)/()+()/(

We add all the numbers together, and all the variables

-((y-4)*2)/()+1

We multiply all the terms by the denominator


-((y-4)*2)+1*()



We calculate terms in parentheses: -((y-4)*2), so:

(y-4)*2

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We add all the numbers together, and all the variables

-(2y-8)

We get rid of parentheses

-2y+8

Back to the equation:

+(-2y+8)



We get rid of parentheses

y-2y+8=0

We add all the numbers together, and all the variables

-1y+8=0

We move all terms containing y to the left, all other terms to the right

-y=-8

y=-8/-1

y=+8

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