6(u+2)=-3(5u-1)+6u

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Solution for 6(u+2)=-3(5u-1)+6u equation: 



6(u+2)=-3(5u-1)+6u

We move all terms to the left:

6(u+2)-(-3(5u-1)+6u)=0

We multiply parentheses

6u-(-3(5u-1)+6u)+12=0



We calculate terms in parentheses: -(-3(5u-1)+6u), so:

-3(5u-1)+6u

We add all the numbers together, and all the variables

6u-3(5u-1)

We multiply parentheses

6u-15u+3

We add all the numbers together, and all the variables

-9u+3

Back to the equation:

-(-9u+3)



We get rid of parentheses

6u+9u-3+12=0

We add all the numbers together, and all the variables

15u+9=0

We move all terms containing u to the left, all other terms to the right

15u=-9

u=-9/15

u=-3/5

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