2(t-2)+2=(2t-5)

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Solution for 2(t-2)+2=(2t-5) equation: 



2(t-2)+2=(2t-5)

We move all terms to the left:

2(t-2)+2-((2t-5))=0

We multiply parentheses

2t-((2t-5))-4+2=0



We calculate terms in parentheses: -((2t-5)), so:

(2t-5)

We get rid of parentheses

2t-5

Back to the equation:

-(2t-5)



We add all the numbers together, and all the variables

2t-(2t-5)-2=0

We get rid of parentheses

2t-2t+5-2=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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