6(u+1)+8u=2(u-3)

Solution for 6(u+1)+8u=2(u-3) equation:

Simplifying
6(u + 1) + 8u = 2(u + -3)

Reorder the terms:
6(1 + u) + 8u = 2(u + -3)
(1 * 6 + u * 6) + 8u = 2(u + -3)
(6 + 6u) + 8u = 2(u + -3)

Combine like terms: 6u + 8u = 14u
6 + 14u = 2(u + -3)

Reorder the terms:
6 + 14u = 2(-3 + u)
6 + 14u = (-3 * 2 + u * 2)
6 + 14u = (-6 + 2u)

Solving
6 + 14u = -6 + 2u

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-2u' to each side of the equation.
6 + 14u + -2u = -6 + 2u + -2u

Combine like terms: 14u + -2u = 12u
6 + 12u = -6 + 2u + -2u

Combine like terms: 2u + -2u = 0
6 + 12u = -6 + 0
6 + 12u = -6

Add '-6' to each side of the equation.
6 + -6 + 12u = -6 + -6

Combine like terms: 6 + -6 = 0
0 + 12u = -6 + -6
12u = -6 + -6

Combine like terms: -6 + -6 = -12
12u = -12

Divide each side by '12'.
u = -1

Simplifying
u = -1