6(t-2)+6t=6(2t+3)-10

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Solution for 6(t-2)+6t=6(2t+3)-10 equation: 



6(t-2)+6t=6(2t+3)-10

We move all terms to the left:

6(t-2)+6t-(6(2t+3)-10)=0

We add all the numbers together, and all the variables

6t+6(t-2)-(6(2t+3)-10)=0

We multiply parentheses

6t+6t-(6(2t+3)-10)-12=0



We calculate terms in parentheses: -(6(2t+3)-10), so:

6(2t+3)-10

We multiply parentheses

12t+18-10

We add all the numbers together, and all the variables

12t+8

Back to the equation:

-(12t+8)



We add all the numbers together, and all the variables

12t-(12t+8)-12=0

We get rid of parentheses

12t-12t-8-12=0

We add all the numbers together, and all the variables

-20!=0

There is no solution for this equation

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