-8(x+1)2x=-32

Solution for -8(x+1)2x=-32 equation:

-8(x+1)2x=-32

We move all terms to the left:

-8(x+1)2x-(-32)=0

We add all the numbers together, and all the variables

-8(x+1)2x+32=0

We multiply parentheses

-16x^2-16x+32=0

a = -16; b = -16; c = +32;
Δ = b2-4ac
Δ = -162-4·(-16)·32
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-48}{2*-16}=\frac{-32}{-32}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+48}{2*-16}=\frac{64}{-32}
=-2
$