6(t+2)+1=13

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Solution for 6(t+2)+1=13 equation: 



6(t+2)+1=13

We move all terms to the left:

6(t+2)+1-(13)=0

We add all the numbers together, and all the variables

6(t+2)-12=0

We multiply parentheses

6t+12-12=0

We add all the numbers together, and all the variables

6t=0

t=0/6

t=0

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