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2/3y+3/5y=114
We move all terms to the left:
2/3y+3/5y-(114)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: 5y!=0We calculate fractions
y!=0/5
y!=0
y∈R
10y/15y^2+9y/15y^2-114=0
We multiply all the terms by the denominator
10y+9y-114*15y^2=0
We add all the numbers together, and all the variables
19y-114*15y^2=0
Wy multiply elements
-1710y^2+19y=0
a = -1710; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-1710)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-1710}=\frac{-38}{-3420} =1/90 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-1710}=\frac{0}{-3420} =0 $
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