6(r-5)-5(r-1)=2(r+5)

Solution for 6(r-5)-5(r-1)=2(r+5) equation:

6(r-5)-5(r-1)=2(r+5)

We move all terms to the left:

6(r-5)-5(r-1)-(2(r+5))=0

We multiply parentheses

6r-5r-(2(r+5))-30+5=0


We calculate terms in parentheses: -(2(r+5)), so:

2(r+5)

We multiply parentheses

2r+10

Back to the equation:

-(2r+10)


We add all the numbers together, and all the variables

r-(2r+10)-25=0

We get rid of parentheses

r-2r-10-25=0

We add all the numbers together, and all the variables

-1r-35=0

We move all terms containing r to the left, all other terms to the right

-r=35

r=35/-1

r=-35