1/(2x-2)=10

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Solution for 1/(2x-2)=10 equation: 



1/(2x-2)=10

We move all terms to the left:

1/(2x-2)-(10)=0



Domain of the equation: (2x-2)!=0

We move all terms containing x to the left, all other terms to the right

2x!=2

x!=2/2

x!=1

x∈R



We multiply all the terms by the denominator


-10*(2x-2)+1=0

We multiply parentheses

-20x+20+1=0

We add all the numbers together, and all the variables

-20x+21=0

We move all terms containing x to the left, all other terms to the right

-20x=-21

x=-21/-20

x=1+1/20

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