6(p+3)=5(2-p)+7-12

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Solution for 6(p+3)=5(2-p)+7-12 equation: 



6(p+3)=5(2-p)+7-12

We move all terms to the left:

6(p+3)-(5(2-p)+7-12)=0

We add all the numbers together, and all the variables

6(p+3)-(5(-1p+2)+7-12)=0

We multiply parentheses

6p-(5(-1p+2)+7-12)+18=0



We calculate terms in parentheses: -(5(-1p+2)+7-12), so:

5(-1p+2)+7-12

We add all the numbers together, and all the variables

5(-1p+2)-5

We multiply parentheses

-5p+10-5

We add all the numbers together, and all the variables

-5p+5

Back to the equation:

-(-5p+5)



We get rid of parentheses

6p+5p-5+18=0

We add all the numbers together, and all the variables

11p+13=0

We move all terms containing p to the left, all other terms to the right

11p=-13

p=-13/11

p=-1+2/11

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