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(4x+2)=4x-12(x-1)
We move all terms to the left:
(4x+2)-(4x-12(x-1))=0
We get rid of parentheses
4x-(4x-12(x-1))+2=0
We calculate terms in parentheses: -(4x-12(x-1)), so:We get rid of parentheses
4x-12(x-1)
We multiply parentheses
4x-12x+12
We add all the numbers together, and all the variables
-8x+12
Back to the equation:
-(-8x+12)
4x+8x-12+2=0
We add all the numbers together, and all the variables
12x-10=0
We move all terms containing x to the left, all other terms to the right
12x=10
x=10/12
x=5/6
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