6(n-7)=2(2n-5)

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Solution for 6(n-7)=2(2n-5) equation: 



6(n-7)=2(2n-5)

We move all terms to the left:

6(n-7)-(2(2n-5))=0

We multiply parentheses

6n-(2(2n-5))-42=0



We calculate terms in parentheses: -(2(2n-5)), so:

2(2n-5)

We multiply parentheses

4n-10

Back to the equation:

-(4n-10)



We get rid of parentheses

6n-4n+10-42=0

We add all the numbers together, and all the variables

2n-32=0

We move all terms containing n to the left, all other terms to the right

2n=32

n=32/2

n=16

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