6(2n-5)=2(n-7)

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Solution for 6(2n-5)=2(n-7) equation: 



6(2n-5)=2(n-7)

We move all terms to the left:

6(2n-5)-(2(n-7))=0

We multiply parentheses

12n-(2(n-7))-30=0



We calculate terms in parentheses: -(2(n-7)), so:

2(n-7)

We multiply parentheses

2n-14

Back to the equation:

-(2n-14)



We get rid of parentheses

12n-2n+14-30=0

We add all the numbers together, and all the variables

10n-16=0

We move all terms containing n to the left, all other terms to the right

10n=16

n=16/10

n=1+3/5

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