6(n-1)=2(n-+1)

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Solution for 6(n-1)=2(n-+1) equation: 



6(n-1)=2(n-+1)

We move all terms to the left:

6(n-1)-(2(n-+1))=0

We add all the numbers together, and all the variables

6(n-1)-(2(+n))=0

We multiply parentheses

6n-(2(+n))-6=0



We calculate terms in parentheses: -(2(+n)), so:

2(+n)

We multiply parentheses

2n

Back to the equation:

-(2n)



We add all the numbers together, and all the variables

4n-6=0

We move all terms containing n to the left, all other terms to the right

4n=6

n=6/4

n=1+1/2

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