-6(t+1)-t-12=-7(t+4)+10

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Solution for -6(t+1)-t-12=-7(t+4)+10 equation: 



-6(t+1)-t-12=-7(t+4)+10

We move all terms to the left:

-6(t+1)-t-12-(-7(t+4)+10)=0

We add all the numbers together, and all the variables

-1t-6(t+1)-(-7(t+4)+10)-12=0

We multiply parentheses

-1t-6t-(-7(t+4)+10)-6-12=0



We calculate terms in parentheses: -(-7(t+4)+10), so:

-7(t+4)+10

We multiply parentheses

-7t-28+10

We add all the numbers together, and all the variables

-7t-18

Back to the equation:

-(-7t-18)



We add all the numbers together, and all the variables

-7t-(-7t-18)-18=0

We get rid of parentheses

-7t+7t+18-18=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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