6(n+2)=3(n+1)

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Solution for 6(n+2)=3(n+1) equation: 



6(n+2)=3(n+1)

We move all terms to the left:

6(n+2)-(3(n+1))=0

We multiply parentheses

6n-(3(n+1))+12=0



We calculate terms in parentheses: -(3(n+1)), so:

3(n+1)

We multiply parentheses

3n+3

Back to the equation:

-(3n+3)



We get rid of parentheses

6n-3n-3+12=0

We add all the numbers together, and all the variables

3n+9=0

We move all terms containing n to the left, all other terms to the right

3n=-9

n=-9/3

n=-3

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