3(2y-1)=39-2(y+2)

Solution for 3(2y-1)=39-2(y+2) equation:

3(2y-1)=39-2(y+2)

We move all terms to the left:

3(2y-1)-(39-2(y+2))=0

We multiply parentheses

6y-(39-2(y+2))-3=0


We calculate terms in parentheses: -(39-2(y+2)), so:

39-2(y+2)

determiningTheFunctionDomain
-2(y+2)+39

We multiply parentheses

-2y-4+39

We add all the numbers together, and all the variables

-2y+35

Back to the equation:

-(-2y+35)


We get rid of parentheses

6y+2y-35-3=0

We add all the numbers together, and all the variables

8y-38=0

We move all terms containing y to the left, all other terms to the right

8y=38

y=38/8

y=4+3/4