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(2x+7)(3x-8)+25=0
We multiply parentheses ..
(+6x^2-16x+21x-56)+25=0
We get rid of parentheses
6x^2-16x+21x-56+25=0
We add all the numbers together, and all the variables
6x^2+5x-31=0
a = 6; b = 5; c = -31;
Δ = b2-4ac
Δ = 52-4·6·(-31)
Δ = 769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{769}}{2*6}=\frac{-5-\sqrt{769}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{769}}{2*6}=\frac{-5+\sqrt{769}}{12} $
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