(4b-3)(4b-3)=0

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Solution for (4b-3)(4b-3)=0 equation: 



(4b-3)(4b-3)=0

We multiply parentheses ..

(+16b^2-12b-12b+9)=0

We get rid of parentheses

16b^2-12b-12b+9=0

We add all the numbers together, and all the variables

16b^2-24b+9=0

a = 16; b = -24; c = +9;
Δ = b2-4ac
Δ = -242-4·16·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{24}{32}=3/4$

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