6(k-6)=2(3-3k)+6

Solution for 6(k-6)=2(3-3k)+6 equation:

6(k-6)=2(3-3k)+6

We move all terms to the left:

6(k-6)-(2(3-3k)+6)=0

We add all the numbers together, and all the variables

6(k-6)-(2(-3k+3)+6)=0

We multiply parentheses

6k-(2(-3k+3)+6)-36=0


We calculate terms in parentheses: -(2(-3k+3)+6), so:

2(-3k+3)+6

We multiply parentheses

-6k+6+6

We add all the numbers together, and all the variables

-6k+12

Back to the equation:

-(-6k+12)


We get rid of parentheses

6k+6k-12-36=0

We add all the numbers together, and all the variables

12k-48=0

We move all terms containing k to the left, all other terms to the right

12k=48

k=48/12

k=4