(x+2)3=x3+6x2+12x+8

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Solution for (x+2)3=x3+6x2+12x+8 equation: 



(x+2)3=x3+6x^2+12x+8

We move all terms to the left:

(x+2)3-(x3+6x^2+12x+8)=0

We multiply parentheses

-(x3+6x^2+12x+8)+3x+6=0

We get rid of parentheses

-6x^2-x3-12x+3x-8+6=0

We add all the numbers together, and all the variables

-6x^2-1x^3-9x-2=0

We do not support expression: x^3

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