6(k-5)=-3(7k+1)

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Solution for 6(k-5)=-3(7k+1) equation:



6(k-5)=-3(7k+1)
We move all terms to the left:
6(k-5)-(-3(7k+1))=0
We multiply parentheses
6k-(-3(7k+1))-30=0
We calculate terms in parentheses: -(-3(7k+1)), so:
-3(7k+1)
We multiply parentheses
-21k-3
Back to the equation:
-(-21k-3)
We get rid of parentheses
6k+21k+3-30=0
We add all the numbers together, and all the variables
27k-27=0
We move all terms containing k to the left, all other terms to the right
27k=27
k=27/27
k=1

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