6(k-3)+8=-3(1-2k)-7

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Solution for 6(k-3)+8=-3(1-2k)-7 equation:



6(k-3)+8=-3(1-2k)-7
We move all terms to the left:
6(k-3)+8-(-3(1-2k)-7)=0
We add all the numbers together, and all the variables
6(k-3)-(-3(-2k+1)-7)+8=0
We multiply parentheses
6k-(-3(-2k+1)-7)-18+8=0
We calculate terms in parentheses: -(-3(-2k+1)-7), so:
-3(-2k+1)-7
We multiply parentheses
6k-3-7
We add all the numbers together, and all the variables
6k-10
Back to the equation:
-(6k-10)
We add all the numbers together, and all the variables
6k-(6k-10)-10=0
We get rid of parentheses
6k-6k+10-10=0
We add all the numbers together, and all the variables
=0
k=0/1
k=0

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